## Chemistry and Chemical Reactivity (9th Edition)

From the principle of conservation of energy and assuming not all ice melts: $(240\ mL\times 1\ \frac{g}{mL})\times (4.184\ \frac{J}{g\cdot{K}} )\times(10.5K-0K)\ =m\times (333\ \frac{J}{g})$ $m=31.7\ g\lt 45\ g$ since the mass from our calculation is less than the initial mass of the ice cube put into the soda, we know there is some ice remaining in the mixture. Therefore, the remaining ice is: $45g-31.7g=13.3\ g$ So the answer is: (a)