Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning

Chapter 5 Principles of Chemical Reactivity: Energy and Chemical Reactions - Study Questions - Page 217e: 79

Answer

$T=4.81\ ^{\circ} C$

Work Step by Step

From the conservation of energy principle: $500.\ mL\times 1\ g/mL\times 4.184\ J/g.K \times (20.0-T)\ K=[333\ J/g+4.184\ J/g.K\times (T-0.0)]\times 2\times45\ g$ $T=4.81\ ^{\circ} C$

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