Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179j: 121

Answer

$0.00110\ M$

Work Step by Step

The number of moles is preserved: $\{[(25.0\ mL\times 0.110\ M)/100\ mL] \times10.0\ mL\}/250.0\ mL=0.00110\ M$
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