Answer
A
Work Step by Step
We use stoichiometry to find:
$1.0\ g\ MgO\div40.30\ g\ MgO/mol\ MgO\times\dfrac{2\ mol\ Mg}{2\ mol\ MgO}\times 24.30\ g\ Mg/mol\ Mg=0.60\ g\ Mg$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - 4-1 Mass Relationships in Chemical Reactions: Stoichiometry - Review & Check for Section 4-1 - Page 143: 2
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