Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - 4-1 Mass Relationships in Chemical Reactions: Stoichiometry - Review & Check for Section 4-1 - Page 143: 2



Work Step by Step

We use stoichiometry to find: $1.0\ g\ MgO\div40.30\ g\ MgO/mol\ MgO\times\dfrac{2\ mol\ Mg}{2\ mol\ MgO}\times 24.30\ g\ Mg/mol\ Mg=0.60\ g\ Mg$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.