#### Answer

B

#### Work Step by Step

Reaction: $Al+3/2\ Cl_2\rightarrow AlCl_3$
$0.40\ mol\times\dfrac{3/2}{1}=0.60\ mol$

Chegg costs money, GradeSaver solutions are free!

Published by
Cengage Learning

ISBN 10:
1133949649

ISBN 13:
978-1-13394-964-0

B

Reaction: $Al+3/2\ Cl_2\rightarrow AlCl_3$
$0.40\ mol\times\dfrac{3/2}{1}=0.60\ mol$

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.