Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 2 Atoms, Molecules, and Ions - Study Questions - Page 95f: 106


$3.2\times10^{-4}\ mol$ $1.9\times10^{20}\ atoms$

Work Step by Step

Atomic weight (g/mol): $Fe: 55.845$ Number of moles: $18\times10^{-3}\ g \div 55.845\ g/mol = 3.2\times10^{-4}\ mol$ Number of atoms: $3.2\times10^{-4}\ mol \times 6.022 \times 10^{23}\ atom/mol = 1.9\times10^{20}\ atoms$
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