Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 2 Atoms, Molecules, and Ions - 2-10 Chemical Analysis: Determining Compound Formulas - Applying Chemical Principles - Questions: 2

Answer

$\rho_{Ar}=1.78\ g/L$

Work Step by Step

The problem states that the air density is the sum of the products of densities of its constituents by their volume fraction, so from the data given: Air (dry, $CO_2$ free): $\rho= 1.29327 \ g/L$, $20.96\%\ O_2,\ 78.11\%\ N_2,\ 0.930\%\ Ar$ $O_2$:$\rho= 1.42952\ g/L$ $N_2$:$\rho= 1.25092\ g/L$ So: $1.29327=20.96/100\times1.42952+78.11/100\times1.25092+0.930/100\times \rho_{Ar}$ $\rho_{Ar}=1.78\ g/L$
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