## Chemistry and Chemical Reactivity (9th Edition)

$0.16218\ L$
The mass of $m=0.20389 g$ corresponds to nitrogen (with argon) that remains after oxygen, water and carbon dioxide are removed, and this gas has a density of $\rho= 1.25718\ g/L$, hence the volume of the globe is given by: $V= m/\rho=0.16218\ L$