Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 17 Principles of Chemical Reactivity: Other Aspects of Aqueous Equilibria - Study Questions - Page 677e: 92

Answer

$K=3.75\times10^{-6}$ Left

Work Step by Step

$K=[OH^-]^2/[CN^-]^2=Ksp(Zn(OH)_2)/Ksp(Zn(CN)_2)$ $K=3\times10^{-17}/(8\times10^{-12})$ $K=3.75\times10^{-6}$ Since $K < 1$, the equilibrium lie predominantly to the left.
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