Answer
Sr(OH)2
Work Step by Step
$[OH^-]=10^{pH-14}$
$[OH^-]=0.041\ M$
$[A^{2+}]=0.02\ M$
Assuming complete dissociation:
$[A^{2+}]=[A(OH)_2]_0$
$2.50\ g \div M\div 1.00\ L=0.02\ mol/L$
$M=122.74\ g/mol\rightarrow A=Sr$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 16 Principles of Chemical Reactivity: The Chemistry of Acids and Bases - Study Questions - Page 629e: 85
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