Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 16 Principles of Chemical Reactivity: The Chemistry of Acids and Bases - Study Questions - Page 629e: 83

Answer

$pH=2.68$

Work Step by Step

Molarity: $2\cdot 0.325\ g\div 180.16\ g/mol\div 0.225\ L=0.016\ M$ $K_a=[H_3O^+][A^-]/[HA]$ $3.27\cdot10^{-4}=x\cdot x/(0.016-x)$ $x=0.0021\ M$ $pH=-log([H_3O^+])$ $pH=2.68$
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