Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 16 Principles of Chemical Reactivity: The Chemistry of Acids and Bases - Study Questions - Page 629c: 51


See the answer below.

Work Step by Step

$K_a=[H_3O^+][CN^-]/[HCN]$ $[H_3O^+]=[CN^-]=x$ $[HCN]=0.025-x$ $4\cdot10^{-10}=x^2/(0.025-x)$ $x=3.16\cdot10^{-6}\ M=[H_3O^+]=[CN^-]$ $[HCN]\approx0.025\ M$ $pH=-log(H_3O^+)$ $pH=5.50$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.