Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 13 Solutions and Their Behavior - Study Questions - Page 505a: 19


$0.0022\ g$

Work Step by Step

From Henry's Law: $S=k_HP$ $S=1.3\times10^{-3}\ mol/\times 40\ mmHg\times1\ bar/750.06\ mmHg=6.93\times10^{-5}\ mol/kg$ Assuming a density of 1 kg per liter: $6.93\times10^{-5}\ mol/kg\times 1.0\ kg/L\times 1.0\ L\times 32.00\ g/mol=0.0022\ g$
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