Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 13 Solutions and Their Behavior - Study Questions - Page 505a: 12


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Work Step by Step

a) $28\ ppb = 28\times10^{-9}\ kg_{solute}/kg_{solvent}$ To molality: $28\times10^{-9}\ kg_{solute}/kg_{solvent}\div 107.87\times10^{-3}\ kg_{solute}/mol_{solute}=2.60\times 10^{-7}\ m$ b) $1.0\times10^2\ g_{Ag} \div28\times10^{-9}\ g_{Ag}/g_{H2O}\div 1.0\times10^{3}\ g_{H2O}/L=3.57\times10^{6}\ L$
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