Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 12 The Solid State - Study Questions - Page 467e: 59

Answer

$2.774\ g/cm^3$

Work Step by Step

Side length: $2r_{K^+}+2r_{Br^-}=2\times 133+2\times 196=658\ pm=6.58\times 10^{-8}\ cm$ Volume: $(6.58\times 10^{-8}\ cm)^3=2.849\times10^{-22}\ cm^3$ Mass: $(4\times M_K+4\times M_{Br})/N_A=(4\times39.098+4\times79.904)/6.022\times10^{23}=7.904\times10^{-22}\ g$ Density: $7.904\times10^{-22}\ g\div2.849\times10^{-22}\ cm^3=2.774\ g/cm^3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.