Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 12 The Solid State - Study Questions - Page 467e: 51


$855\ nm$

Work Step by Step

$\hat E=E/N_A=h.\nu=h.c/\lambda$ $h.c.N_A=0.120\ J.m/mol$ $\lambda=0.120\div 140000=8.55\times10^{-7}\ m=855\ nm$
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