## Chemistry and Chemical Reactivity (9th Edition)

a) Performing a regression, it follows: $ln\ P(mmHg)=-5311.93\ K/T(K)+18.53$ b,c) Solving for the temperature, we find: $250\ mmHg: 135.25°C$ $650\ mmHg: 167.60°C$ $760\ mmHg: 173.40°C$, which is the normal boiling point. d) From the Clausius-Clapeyron equation, it follows: $\Delta H_v=-5311.93\ K×-0.008314\ kJ/mol.K=44.2\ kJ/mol$