## Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning

# Chapter 11 Intermolecular Forces and Liquids - Study Questions - Page 435c: 38

#### Answer

See the answer below.

#### Work Step by Step

a) Performing a regression, it follows: $ln\ P(mmHg)=-5311.93\ K/T(K)+18.53$ b,c) Solving for the temperature, we find: $250\ mmHg: 135.25°C$ $650\ mmHg: 167.60°C$ $760\ mmHg: 173.40°C$, which is the normal boiling point. d) From the Clausius-Clapeyron equation, it follows: $\Delta H_v=-5311.93\ K×-0.008314\ kJ/mol.K=44.2\ kJ/mol$

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