Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 11 Intermolecular Forces and Liquids - Study Questions - Page 435c: 37


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Work Step by Step

Using the Ideal Gas Law, it follows: $n=(0.00169/760×1\ atm)×1000\ L/((0.082)(301\ K))$ $n=0.00009\ mol$ Thus: $0.00009\ mol×6.022×10^{23}=5.42×10^{19}\ atoms$
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