Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 7 - Section 7.8 - Energy in Chemical Reactions - Additional Questions and Problems - Page 249: 7.86a

Answer

There is a total of 63.0 g in 2.25 mole of $N_2$.

Work Step by Step

1. Determine the molar mass of this compound ($N_2$), and setup the conversion factors: $N: 14.01g * 2= 28.02g $ $ \frac{1 \space mole \space (N_2)}{ 28.02 \space g \space (N_2)}$ and $ \frac{ 28.02 \space g \space (N_2)}{1 \space mole \space (N_2)}$ 2. Calculate the mass: $ 2.25 \space mole \times \frac{ 28.02 \space g}{1 \space mole} = 63.0 \space g$
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