Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 6 - Sections 6.1-6.10 - Exercises - Problems by Topic - Page 290: 84a

Answer

$\frac{1}{2}$$N_{2}(g)$$+$$O_{2}(g)$$->$$NO_{2}(g)$

Work Step by Step

$\Delta$$H^{\circ}_{f}$$=$$33.2 kJ/mol$
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