Answer
$\Delta$$H^{\circ}_{f}$$=-45.9 kJ/mol$
Work Step by Step
$\frac{1}{2}$$N_{2}(g)$$+$$\frac{3}{2}$$H_{2}(g)$$->NH_{3}(g)$
Chemistry: A Molecular Approach (3rd Edition)
by Tro, Nivaldo J.
Published by
Prentice Hall
ISBN 10:
0321809246
ISBN 13:
978-0-32180-924-7
Chapter 6 - Sections 6.1-6.10 - Exercises - Problems by Topic - Page 290: 83a
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