Answer
Answer = -1.65E5
STEP 1
50ml • $\frac{1.0g}{ml}$
STEP 2
mC$\Delta$T
50g • 4.18 • (23.7-22.5)
= 250.8 J =$q_{solution}$
$q_{rxn}$= - $q_{solution}$ = -250.8J
STEP 3
.103g Zn • $\frac{mol Zn}{65.38g}$
=.001575 mol Zn
STEP 4
$\frac{-250J}{.001575 mol}$ = -1.6E5
Work Step by Step
STEP 1
50ml • $\frac{1.0g}{ml}$
STEP 2
mC$\Delta$T
50g • 4.18 • (23.7-22.5)
= 250.8 J =$q_{solution}$
$q_{rxn}$= - $q_{solution}$ = -250.8J
STEP 3
.103g Zn • $\frac{mol Zn}{65.38g}$
=.001575 mol Zn
STEP 4
$\frac{-250J}{.001575 mol}$ = -1.6E5
