Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 6 - Sections 6.1-6.10 - Exercises - Problems by Topic - Page 289: 64

Answer

55.9 g $CO_{2}$

Work Step by Step

Mass of $CO_{2}$ produced= $-5.00\times10^{2}\,kJ\times \frac{1\,mol\,CO_{2}}{-393.5\,kJ}\times\frac{44.01\,g\,CO_{2}}{1\,mol\,CO_{2}}$ $=55.9\,g\,CO_{2}$
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