Answer
55.9 g $CO_{2}$
Work Step by Step
Mass of $CO_{2}$ produced=
$-5.00\times10^{2}\,kJ\times \frac{1\,mol\,CO_{2}}{-393.5\,kJ}\times\frac{44.01\,g\,CO_{2}}{1\,mol\,CO_{2}}$
$=55.9\,g\,CO_{2}$
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