Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 5 - Sections 5.1-5.10 - Exercises - Problems by Topic - Page 240: 52

Answer

$P_2=2.84atm$

Work Step by Step

According to Gay-Lussac's law $\frac{P_1}{T_1}=\frac{P_2}{T_2}$ This can be rearranged as $P_2=\frac{P_1T_2}{T_1}$.......eq(1) $T_1=25+273.15=298.15K$ $T_2=355+273.15=628.15K$ We plug in the known values in eq(1) to obtain: $P_2=\frac{1.35\times 628.15}{298.15}=2.84atm$
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