Chapter 5 - Sections 5.1-5.10 - Exercises - Problems by Topic - Page 240: 51

$P_2=4.76atm$

According to Gay-Lussac's law $\frac{P_1}{T_1}=\frac{P_2}{T_2}$ This can be rearranged as $P_2=\frac{P_1T_2}{T_1}$.......eq(1) $T_1=25+273.15=298.15K$ $T_2=1155+273.15=1428.15K$ $P_1=755mmHg\times \frac{1atm}{760mmHg}=0.99342atm$ We plug in the known values in eq(1) to obtain: $P_2=\frac{0.99342\times 1428.15}{298.15}=4.76atm$