#### Answer

$203mol\ NH_{3}$

#### Work Step by Step

Multiply by 1000 to convert the kilograms to grams. Divide by the molar mass to convert to moles then multiply by the mole ratio obtained in the balanced chemical equation.
$4.88kg\ N_{2}H_{4}\times\frac{1000g}{1kg}\times\frac{1mol\ N_{2}H_{4}}{32.0452g\ N_{2}H_{4}}\times\frac{4mol\ NH_{3}}{3mol\ N_{2}H_{4}}=203mol\ NH_{3}$