## Chemistry: A Molecular Approach (3rd Edition)

$203mol\ NH_{3}$
Multiply by 1000 to convert the kilograms to grams. Divide by the molar mass to convert to moles then multiply by the mole ratio obtained in the balanced chemical equation. $4.88kg\ N_{2}H_{4}\times\frac{1000g}{1kg}\times\frac{1mol\ N_{2}H_{4}}{32.0452g\ N_{2}H_{4}}\times\frac{4mol\ NH_{3}}{3mol\ N_{2}H_{4}}=203mol\ NH_{3}$