Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic - Page 186: 28d


$203mol\ NH_{3}$

Work Step by Step

Multiply by 1000 to convert the kilograms to grams. Divide by the molar mass to convert to moles then multiply by the mole ratio obtained in the balanced chemical equation. $4.88kg\ N_{2}H_{4}\times\frac{1000g}{1kg}\times\frac{1mol\ N_{2}H_{4}}{32.0452g\ N_{2}H_{4}}\times\frac{4mol\ NH_{3}}{3mol\ N_{2}H_{4}}=203mol\ NH_{3}$
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