## Chemistry: A Molecular Approach (3rd Edition)

$2.7mol\ NH_{3}$
Divide by the molar mass to convert to moles then multiply by the mole ratio obtained in the balanced chemical equation. $65.3g\ N_{2}H_{4}\times\frac{1mol\ N_{2}H_{4}}{32.0452g\ N_{2}H_{4}}\times\frac{4mol\ NH_{3}}{3mol\ N_{2}H_{4}}=2.7mol\ NH_{3}$