Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic - Page 186: 28c


$2.7mol\ NH_{3}$

Work Step by Step

Divide by the molar mass to convert to moles then multiply by the mole ratio obtained in the balanced chemical equation. $65.3g\ N_{2}H_{4}\times\frac{1mol\ N_{2}H_{4}}{32.0452g\ N_{2}H_{4}}\times\frac{4mol\ NH_{3}}{3mol\ N_{2}H_{4}}=2.7mol\ NH_{3}$
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