Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Cumulative Problems - Page 134: 123


$1.80\times10^{2}\frac{g\ Cl}{1\ year}$

Work Step by Step

If the car emits $25g\ CF_{2}Cl_{2}$ a month then it will emmit $25\times 12=300g \ CF_{2}Cl_{2}$ in a year. Divide this number by the molar mass of $CF_{2}Cl_{2}$ to get the number of moles of $CF_{2}Cl_{2}$. Then multiply by 2 because there are 2 $Cl$ for every mole of $CF_{2}Cl_{2}$. Finally, multiply by the molar mass of $Cl$. $300g\ CF_{2}Cl_{2}\times\frac{1 mol\ CF_{2}Cl_{2}}{120.91g\ CF_{2}Cl_{2}}\times2\times\frac{35.45g\ Cl}{1mol\ Cl}=\frac{1.80\times10^{2}g\ Cl}{1\ year}$
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