Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Cumulative Problems - Page 134: 119

Answer

$1.50\times10^{24}$ molecules of ethanol

Work Step by Step

Multiply the volume of 145mL by the given density of ethanol (remember that $cm^{3}$ is the same as milliliters). Then multiply by the molar mass of ethanol which can be calculated by adding the molar mass of its constituent elements. Finally, multiply by Avogadro's number to get the number of molecules. Notice how all units but molecules cancel each other out. $145 mL \times \frac{0.789g}{1mL}\times\frac{1 mol}{46.068g}\times\frac{6.022\times10^{23}molecules}{1 mol} = 1.50\times10^{24} molecules$
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