Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Challenge Problems - Page 84: 127

Answer

63.67 g/mol

Work Step by Step

7.36g Cu + 0.51g Zn = 7.87g sample ($\frac{7.36g Cu}{7.87g sample}$)($\frac{63.55 g Cu}{mol Cu}$) + ($\frac{0.51g Zn}{7.87g sample}$)($\frac{65.41 g Zn}{mol Zn}$) = 63.67 g/mol
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