Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Challenge Problems - Page 84: 124a

Answer

$x_{296_{Wt}}= 0.72$ $x_{297_{Wt}}= 0.04$ $x_{298_{Wt}}=0.24$

Work Step by Step

To calculate the natural abundance of each of Wt isotope we need to divide the number of atoms of each isotope in the sample with the total number of atoms in the sample (50). $x_{296_{Wt}}= \frac{N_{296_{Wt}}}{N_{total}}= \frac{36}{50}= 0.72$ $x_{297_{Wt}}= \frac{N_{297_{Wt}}}{N_{total}}= \frac{2}{50}= 0.04$ $x_{298_{Wt}}= \frac{N_{298_{Wt}}}{N_{total}}= \frac{12}{50}= 0.24$
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