Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 14 - Sections 14.1-14.9 - Exercises - Review Questions - Page 687: 6

Answer

$$ K_{1} \times K_{2}$$

Work Step by Step

If two or more chemical equations are added to create an overall equation, you must multiply the relating equilibrium constants by each other to get the final equilibrium constant. Therefore, the equilibrium constant for this reaction is $ K_{1} \times K_{2}$.
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