Answer
$Kp=1.0648\times10^{19}$
The products are favored at equilibrium.
Work Step by Step
It is observed,all the coefficients of that reaction were multiplied by 3.Thus, the new equilibrium constant is equal to the old one to the power of 3
$Kp=(2.2\times10^{6})^{3}$=$1.0648\times10^{19}$
Since $Kp>1$,the products will be favored at equilibrium.
