Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 14 - Sections 14.1-14.9 - Exercises - Problems by Topic - Page 688: 21b

Answer

$\frac{[NO]^{2}[Br2]}{[BrNO]^{2}}$

Work Step by Step

The equilibrium constant, k, is defined as the products to the power of the coefficient over the reaction to the power of the coefficient. In this case, the products are NO and Br2. NO has a coefficient of two so it is raised to the 2 power. Br2 has a coefficient of one so it is raised to the first power. The reactant is BrNO that also has a coefficient of 2 raising it to the second power. Therefore the rate constant is $\frac{[NO]^{2}[Br2]}{[BrNO]^{2}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.