Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 14 - Sections 14.1-14.9 - Exercises - Problems by Topic - Page 688: 21a

Answer

$\frac{[SbCl3][Cl2]}{[SbCl3]}$

Work Step by Step

The equilibrium constant, k, is defined as the products to the power of the coefficient over the reaction to the power of the coefficient. In this case, the products are SbCl3 and Cl2, all with a coefficient of one. The reactant is SbCl3 that also has a coefficient of 1 giving the rate constant of $\frac{[SbCl3][Cl2]}{[SbCl3]}$
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