Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 13 - Sections 13.1-13.7 - Exercises - Problems by Topic - Page 638: 25b

Answer

$1.8\times10^{-3}M/s$

Work Step by Step

$r_{av}= -\frac{1}{2}\times\frac{\Delta [HBr]}{\Delta t}$ $=-\frac{1}{2}\times\frac{0.512M-0.600M}{(25-0)s}= 1.8\times10^{-3}M/s$
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