Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 7 - Atomic Structure and Periodicity - Exercises - Page 342: 43


$9.38\times 10^{14}Hz$ to $1.07\times 10^{15}Hz$

Work Step by Step

We know that $v=\frac{c}{\lambda}$ $\implies v=\frac{3\times 10^8\frac{m}{s}}{\lambda}\times \frac{10^9nm}{1m}$.......eq(1) If $\lambda=280nm$ then substituting values in equation(1),we obtain $v=1.07\times 10^{15}Hz$ and if $\lambda=320nm$ then equation gives us $v=9.38\times 10^{14}Hz$
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