Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 7 - Atomic Structure and Periodicity - Exercises - Page 342: 41


$v=3\times 10^{10}Hz$ $E=2\times 10^{-23}\frac{J}{photon}$ $E=12\frac{J}{mol}$

Work Step by Step

We know that $v=\frac{c}{\lambda}$ We plug in the known values to obtain: $v=\frac{2.9979\times 10^8}{0.01}$ $v=3\times 10^{10}Hz$ As $E=h\nu$ We plug in th known values to obtain: $E=6.626\times 10{-34}\times (3\times 10^{10})$ $E=2\times 10^{-23}\frac{J}{photon}$ We know that $h=6.626\times 10^{-34}Js$ $\implies E=2\times 10^{23}\frac{J}{photon}\times 6.022\times 10^{23}\frac{photons}{mol}$ $E=12\frac{J}{mol}$
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