Answer
$v=3\times 10^{10}Hz$
$E=2\times 10^{-23}\frac{J}{photon}$
$E=12\frac{J}{mol}$
Work Step by Step
We know that
$v=\frac{c}{\lambda}$
We plug in the known values to obtain:
$v=\frac{2.9979\times 10^8}{0.01}$
$v=3\times 10^{10}Hz$
As $E=h\nu$
We plug in th known values to obtain:
$E=6.626\times 10{-34}\times (3\times 10^{10})$
$E=2\times 10^{-23}\frac{J}{photon}$
We know that $h=6.626\times 10^{-34}Js$
$\implies E=2\times 10^{23}\frac{J}{photon}\times 6.022\times 10^{23}\frac{photons}{mol}$
$E=12\frac{J}{mol}$
