Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 6 - Thermochemistry - Exercises: 52

Answer

a. 900 J b. $26.\frac{J}{^\circ C*mol}$ c. $1.63*10^{3}\text{ grams}$

Work Step by Step

a. $q=mc\Delta T$ $q=150.0*0.24*25=900$ J b. $\frac{0.24\text{ J}}{^\circ C*g}*\frac{107.8682\text{ gram}}{1\text{ mole}}=26.\frac{J}{^\circ C*mol}$ c. $1250=m*0.24*3.2$ $m=1.63*10^{3}\text{ grams}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.