## Chemistry 9th Edition

a. 900 J b. $26.\frac{J}{^\circ C*mol}$ c. $1.63*10^{3}\text{ grams}$
a. $q=mc\Delta T$ $q=150.0*0.24*25=900$ J b. $\frac{0.24\text{ J}}{^\circ C*g}*\frac{107.8682\text{ gram}}{1\text{ mole}}=26.\frac{J}{^\circ C*mol}$ c. $1250=m*0.24*3.2$ $m=1.63*10^{3}\text{ grams}$