Answer
a. 900 J
b. $26.\frac{J}{^\circ C*mol}$
c. $1.63*10^{3}\text{ grams}$
Work Step by Step
a.
$q=mc\Delta T$
$q=150.0*0.24*25=900$ J
b.
$\frac{0.24\text{ J}}{^\circ C*g}*\frac{107.8682\text{ gram}}{1\text{ mole}}=26.\frac{J}{^\circ C*mol}$
c.
$1250=m*0.24*3.2$
$m=1.63*10^{3}\text{ grams}$
