Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 6 - Thermochemistry - Exercises - Page 287: 50


a. $\Delta H = \Delta E$ b. $\Delta H < \Delta E$ c. $\Delta H > \Delta E$

Work Step by Step

Note that $\Delta H = \Delta E +P\Delta V$. a. The number of liters remains the same. Therefore $\Delta V$ is 0 and $\Delta H = \Delta E$. b. The number of liters decreases from 4 to 2. Therefore $\Delta V<0$ and $\Delta H < \Delta E$ c. The number of liters increases from 9 to 10. Therefore $\Delta V>0$ and $\Delta H > \Delta E$
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