Answer
-21kJ
Work Step by Step
1) $\Delta$E = q + w (The internal energy is the sum of the heat and work.)
2) $\Delta$E = -125kJ + 104 kJ = -21kJ (Heat is being released, -125kJ. Work is being absorbed, 104kJ. The sum is -21kJ.)
Chemistry 9th Edition
by Zumdahl, Steven S.; Zumdahl, Susan A.
Published by
Cengage Learning
ISBN 10:
1133611095
ISBN 13:
978-1-13361-109-7
Chapter 6 - Thermochemistry - Exercises - Page 286: 30
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