Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Exercises - Page 131: 94


Empirical: $C_{3}H_{4}O_{3}$ Molecular: $C_{6}H_{8}O_{6}$

Work Step by Step

16.01mg$CO_{2}(\frac{12gC}{44.01gCO_{2}})$=4.365mgC/10.68mg=40.87%C $4.37mgH_{2}O(\frac{2gH}{18.02gH_{2}O})$=0.485H/10.68mg=4.54%H 100%-40.87%-4.57%=54.6%O $\frac{40.87gH}{12g/mol}=3.4molC$ $\frac{4.54gH}{1g/mol}=4.54molH$ $\frac{54.6gO}{16g/mol}=3.4molO$ $\frac{4.54mol}{3.4mol}=1.3x3=4$ $MW=3M_{C}+4M_{H}+3M_{O}$ MW=3(12)+4(1)+3(16) MW=88g/mol $\frac{176.1g/mol}{88g/mol}\approx2$
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