Answer
a) 2 C6H6(l) + 15 O2(g) => 12 CO2(g) + 6 H2O(g)
b) 2 C4H10(g) + 13 O2(g) => 8 CO2(g) + 10 H2O(g)
c) C12H22O11(s) + 12 O2(g) => 12 CO2(g) + 11 H2O(g)
d) 4 Fe(s) + 3 O2(g) => 2 Fe2O3(s)
e) 4 FeO(s) + O2(g) => 2 Fe2O3(s)
Work Step by Step
a) To achieve balance in the combustion reaction represented by the formulas C6H6(l) + O2(g) => CO2(g) + H2O(g), it's essential to ensure that all the carbon in C6H6 ultimately becomes carbon in CO2, and all the hydrogen in C6H6 transforms into hydrogen in H2O. Balancing the carbon and hydrogen atoms necessitates the presence of 6 CO2 molecules and 3 H2O molecules for every 1 molecule of C6H6. Oxygen is adjusted last. Considering 15 oxygen atoms in 6 CO2 molecules and 3 H2O molecules, 15/2 O2 molecules are required to account for the 15 oxygen atoms on the reactant side.
b) The formulas of the reactants and products are C4H10(g) + O2(g) => CO2(g) + H2O(g).
c,d,e) The equation has been given and the rest is to start balancing the metals and then by balancing the amounts of metals, we are going to check the other atoms.
