Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 2 - Atoms, Molecules, and Ions - Exercises: 48

Answer

$6.40*10^{-13}$ zirkombs.

Work Step by Step

We divide each of the charges by the smallest charge to find: $$\frac{2.56*10^{-12}}{6.40*10^{-13}}=4$$ $$\frac{7.68*10^{-12}}{6.40*10^{-13}}=12$$ $$\frac{3.84*10^{-12}}{6.40*10^{-13}}=6$$ $$\frac{6.40*10^{-13}}{6.40*10^{-13}}=1$$ Because $6.40*10^{-13}$ produced the smallest integer value, the charge of electron is $6.40*10^{-13}$ zirkombs.
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