Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 2 - Atoms, Molecules, and Ions - Exercises - Page 75: 47



Work Step by Step

We know that one negative charge is i.e charge on electron $1.6\times 10^{-19}C$ Given that the total charge on oil drop is $5.93\times 10^{-18}C$ Thus the number of negative charged on the oil drop$=\frac{5.93\times 10^{-18}C}{1.6\times 10^{-19}}=37$
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