## Chemistry 9th Edition

$x=0.176, P=59.2torr$
We know that according to Raoult's law $P_{soln}=P^{\circ}x$ We plug in the known values to obtain: $x_{H_2O}=0.824$ $\implies x_{solute}=1-x_{solvent}$ $x_{solute}=1-0.824=0.176$ Now at $45C^{\circ}$ $P_{H_2O}=0.824(71.9torr)=59.2 torr$