Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 11 - Properties of Solutions - Exercises - Page 545: 50

Answer

$2.1\times 10^{-4}\frac{mol}{L}$

Work Step by Step

We know that $C=kP$ We plug in the known values to obtain: $C=\frac{1.3\times 10^{-3}}{L.atm}\times 120torr \times \frac{1atm}{760torr}$ $=2.1\times 10^{-4}\frac{mol}{L}$
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