Answer
$2.1\times 10^{-4}\frac{mol}{L}$
Work Step by Step
We know that
$C=kP$
We plug in the known values to obtain:
$C=\frac{1.3\times 10^{-3}}{L.atm}\times 120torr \times \frac{1atm}{760torr}$
$=2.1\times 10^{-4}\frac{mol}{L}$
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