## Chemistry 9th Edition

(a)$V=3\times 10^5 cm^3$ (b)$V=25cm^3$ (c)$V=3.18cm^3$
We know that $d=\frac{m}{V}$ Where d,m and V stand for density, mass and volume respectively The above equation can be rearranged as $V=\frac{m}{d}$.....eq(1) (a) We plug in the known values in equation (1) for Hydrogen gas to obtain: $V=\frac{25g}{0.000084\frac{g}{cm^3}}$ $V=3\times 10^5 cm^3$ (b) We plug in the known values in equation(1) for water to obtain: $V=\frac{25g}{0.9982\frac{g}{cm^3}}$ $V=25cm^3$ (c) We plug in the known values in equation(1) for iron to obtain: $V=\frac{25g}{7.87\frac{g}{cm^3}}$ $V=3.18cm^3$