Answer
Answer:
Mass of mixture = 959 grams
Work Step by Step
To calculate total mass of mixture, we need to calculate the masses of ethanol and benzene separately.
Ethanol:
1 ml = 1 $cm^{3}$ ........(i)
Thus, 100 mL = 100 $cm^{3}$
From table 1.5, density of ethanol is = 0.789 $\frac{g}{cm^{3}}$
Thus mass = density $\times$ volume = 100 $\times$ 0.789 = 78.9 grams
Mass of Benzene:
Volume = 1 liter = 1000 ml = 1000 $cm^{3}$ ....(From (i))
Given density = 0.880 $\frac{g}{cm^{3}}$
Thus mass = 0.880 $\times$ 1000 = 880. grams
Final or total mass of mixture = 880. + 78.9 = 958.9 grams
With sig figs: 959 g
