Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 1 - Chemical Foundations - Exercises - Page 36: 60


a) -40.°C & -40.°F b) -269°C & -452°F c) 25°C & 77°F d) 3410°C & 6160°F

Work Step by Step

a) Celsius: 233K -273K= -40.°C (remember because of sig figs there must be a decimal point after the zero bc it is significant out to the ones place) Fahrenheit: (-40. x (9/5)) + 32 (-72) + 32= -40.°F b) Celsius: 4K -273K= -269°C Fahrenheit: (-269 x (9/5))+32 (-484.2)+32= 452.2°F With sig figs: -452°F (only significant out to the ones place) c) Celsius: 298K -273K= 25°C Fahrenheit: (25 x (9/5))+32 (45)+32= 77°F d) Celsius: 3680K -273K= 3407°C With sig figs: 3410°C (Only significant out to the tens place) Fahrenheit: (3407 x (9/5))+32 (6132.6)+32= 6164.6°F with sig figs: 6160°F (*IMPORTANT* you should never take the significance of a problem twice so you should use 3407°C instead of 3410°C. You must remember at the end however the answer is only significant out to the tens place)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.